Question

Find the angle of elevation of the top of the pole of height 40root 3 from a point 40meters away

Answer 1

Answer :

Angle of elevation is 60°

Step by step explanation :

Given : Height of pole is 40√3 m and distance of point on ground from the foot of the tower is 40 m.

To find : Angle of elevation

Solution :

→ tan ø = Perpendicular / Base

→ tan ø = AB / BC

→ tan ø = 40√3 meter / 40 meter

→ tan ø = √3

We know that Value of tangent theta is √3 on value of theta at 60°.

Hence the angle of elevation is 60°.

Answer 2

Step-by-step explanation:

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