find the angle of elevation when an object at the top of a building of height 70 m is observed from a point on the ground 70 root 3 m away from the base of the building
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suryaklkodagu:
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Answer:
Angle of elevation is 30°
Step-by-step explanation:
Given Height(Opposite)=70m
Given Distance(Adjacent)=70√ 3
so., tanθ=Opposite/Adjacent
tanθ=70/70√3
tanθ=1/√3
ie., tan 30°
Hope u got ur answer.
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