Question

find the angle of elevations when an object at the top of a building of height 70 m is observed from a point on ground 70√3 m away from base of the building​

Answer 1

Answer:

tan30°

Step-by-step explanation:

in a triangle

perpendicular=70m

base=70√3

NOW

 it goes in the formula of tan

so tanФ=p÷b

then

  tanФ=70÷70√3

tanФ=1/√3

that means

  tan30°

Answer 2

let building be perpendicular to the ground ,height of the building =70mand the length of the ground =70√3

as per the sum,

tanx°=opposite side/adjacent side
tanx°=70/70√3
tanx°=1/√3
x°=30°