Question

Find the angle of intersection of the curve ysquare = 4ax and xsquare =4by.

Answer 1

Hope it helps...!!!

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We have,

y2 = 4ax and x2 = 4by

 
Putting x = 0 and x = 4a1/3 b2/3 in we get,

y = 0 and y = 4a2/3 b1/3

Thus, the two curves intersect at P (4a1/3 b2/3, 4a2/3b1/3) other than the origin (0, 0).

Now,

y2 = 4ax and x2 = 4by

 

Let q be the angle between the tangents to the parabolas y2 = 4ax and x2 = 4by at P.


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