Question

Find the angle of intersection of the spheres x^2+y^2+z^2=29 and x^2+y^2+z^2+4x-6y-8z-47=0 at the point(-4,3,2)

Answer 1

Answer:

x2+y2+z2=29 and x2+y2+z2+4x-6y-8z-47-x2+y2+z2=29 and x2+y2+z2+4x-6y-8z-47-x2+y2+z2=29 and x2+y2+z2+4x-6y-8z-47=x2+y2+z2=29 and x2+y2+z2+4x-6y-8z-47