Find the angle of octagon whose interior angle are in the ratio 8:7:10:9:11:10:8:9
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15
sum of interior angle of octogon is 1080
let interior angles of octogon be
8x+7x+10x+9x+11x+10x+8x+9x=72x
72x=1080
x=1080/72
x=15
so angles are 120° ,105°,150°,135°,165°,150°,120° and 135° respectively
let interior angles of octogon be
8x+7x+10x+9x+11x+10x+8x+9x=72x
72x=1080
x=1080/72
x=15
so angles are 120° ,105°,150°,135°,165°,150°,120° and 135° respectively
kishika:
need one more brainly input
Answered by
5
let the angles of octagon be 8x, 7x, 10x, 9x, 11x, 10x, 8x, 9x.
sum of all angles of octagon= 1080
8x+7x+10x+9x+11x+ 10x+8x+9x.=1080
72x=1080
x=1080/72
x=15
Angles after 8x=120
7x=105... so on
angles are 120° , 105°, 150°, 135°, 165°, 150°, 120°, 135°
sum of all angles of octagon= 1080
8x+7x+10x+9x+11x+ 10x+8x+9x.=1080
72x=1080
x=1080/72
x=15
Angles after 8x=120
7x=105... so on
angles are 120° , 105°, 150°, 135°, 165°, 150°, 120°, 135°
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