Find the angle of projection for which the horizontal rangeof the projectile is double the maximum height attained by the body
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Answer:
Range = u^2 x sin2Θ/g
Height maximum = u^2 x sin^2Θ/2g
According to question
Range = 2 x height
u^2 x sin2Θ/g = 2 x u^2 x sin^2Θ/2g
=sin2Θ = sin^2Θ
= 2sinΘcosΘ = sin^2Θ
= tanΘ = 2
= Θ =tan^-1(2)
Answer= Θ =tan^-1(2)
hope it helped
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