Question

Find the angle of projection for which the maximum height attained and the range are equal for a given initial velocity.
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Answer 1

Answer:

ANSWER

Let θ be the angle of projection for which the horizontal range of the projectile are double

We know that

Formula of height

H=

2g

u

2

sin

2

θ

Formula of range

R=

g

u

2

sin2θ

Now, if maximum height is double of range

H=2R

2g

u

2

sin

2

θ

=2×

g

u

2

sin2θ

sin

2

θ=4(2sinθcosθ)

tanθ=8

θ=tan

−1

(8)

Hence, the angle of projection is tan

−1

(8)

Answer 2

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On which it works

OK!!!!