Question

find the angle of projection of a projectile for which the horizontal range and maximum height are equal?

Answer 1

angle equal to 76 in which the horizontal range and maximum height are equal

Answer 2

Answer:

Explanation:

Let angle of projection is ∅ , u is the intial velocity .

we know,

Maximum Height = u²sin²∅/2g

horizontal range = u²sin2∅/g

A/C to question ,

u²sin²∅/2g = u²sin2∅/g

[ use, sin2x = 2sinx.cosx ]

sin²∅/2 = 2sin∅.cos∅

tan∅ = 4

∅ = tan-¹( 4)

angle of projection = tan-¹(4)

∅=76 degrees