Find the angle of projection so that a body when projected has a horizontal range equal to the maximum height attained
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Explanation:
The angle of projection at which the horizontal range and maximum height of projectile are equal is
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ANSWER
R=
g
u
2
sin2θ
H=
2g
u
2
sin
2
θ
g
u
2
sin2θ
=
2g
u
2
sin
2
θ
2sinθcosθ=
2
sin
2
θ
ucosθ=sinθ
tanθ=4
θ=tan
−1
4
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