Question

Find the angle of this Triangle (See Attachment) +7 points

Answer 1

Answer:

105°

Step-by-step explanation:

∠APR=15°

∠PAR=∠SQD=90°( AS is a transversal on parallel lines AB and CD, so both angles are equal.)

∠PRA=180°-(90°+15°)=180°-105°=75°

so, reqd. angle=∠PRQ=180°-∠PRA=180°-75°=105°

HOPE IT HELPS,

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Answer 2

Step-by-step explanation:

90+Q=180

Q=180-90

Q=90 (liner pair)

90 +15=105

180-105=75

AngleP=75 (of triangle)

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