Question

find the angle of x ... plz do it ..... the one who does it correctly , i will mark it as the brainlliest .....plz dont do if ypu dont know the correct way​

Answer 1

Here u go ♥️♥️♥️♥️

➡️Let DB and AB line is intersecting each other at point P.

⏩Now, APB , APD, BPE, DPE are the triangles.

From triangle, APB we get A= 70°,B=60°

So, A+B+C =180°

=> C= 180-130°

=> C = 50°

⏩Now, angle P = angle P in triangles APB and DPE , So P= 50°(vertically opposite angles)

Now, from triangle DAB ,A=80° and B= 60° thereby we can get D .

⏩A+B+D =180°

=> D = 180°- 140°

=> D= 40°

Therefore , D has angle bisector so ,it will be divided in to two halves = 20° each.

⏩Therefore , DPE triangle E has a bisector .

Now, D+P+E =180°

E = 180-70°

E = 110°

x =E/2 = 55°.

Therefore x= 55°.⏪⏪⏪

HOPE it helps u.......♥️♥️✨✨➡️✨➡️✨✌️✌️