Find the angle which is 4 times its complement is 10 degree less than twice its complement??
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Actually question has two parts
1.) Angle which is 4 times its complementary
Let the smaller angle be x
Bigger angle is 4 times of it i.e 4x
Now, 4x+x=90°
-->5x=90°
-->x=18°
Now smaller angle is x which is 18°
Larger angle = 4× x
--> 4×18=72°
2.)Angle which is 10° less than twice its complement
Let the smaller angle be x
Larger angle = 2x-10
-->(2x-10)+x=90°
x=33° {approx}
Larger angle = 66-10=56°{approx.}
1.) Angle which is 4 times its complementary
Let the smaller angle be x
Bigger angle is 4 times of it i.e 4x
Now, 4x+x=90°
-->5x=90°
-->x=18°
Now smaller angle is x which is 18°
Larger angle = 4× x
--> 4×18=72°
2.)Angle which is 10° less than twice its complement
Let the smaller angle be x
Larger angle = 2x-10
-->(2x-10)+x=90°
x=33° {approx}
Larger angle = 66-10=56°{approx.}
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