Find the angle which is 9 times it's complement.
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Answered by
2
Let the smaller angle be x
then required angles is 9x
x+9x=90
10x=90
x=9
9x=9*9=81 degrees
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then required angles is 9x
x+9x=90
10x=90
x=9
9x=9*9=81 degrees
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Answered by
0
Let the angle be x°
x+9x = 90
10x=90
x=9
9x=81
x+9x = 90
10x=90
x=9
9x=81
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