Question

Find the angle, which is equal to half of its supplement.
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Answer 1

       $\underline{\bold{Answer:}}$

       $60^{o}$

       $\underline{\bold{Step-by-step-explaination:}}$

       $\text{Let the angle be }x^{o}$

       $\text{The supplement of an angle is basically }180^{o} -(\text{The angle itself})$

$\implies \text{Supplement of }x = (180 - x)^{o}$

       $\text{According to the question:}$

       $x = \dfrac{180-x}{2}$

       $\text{Cross multiplying...}$

$\implies 2x = 180-x$

       $\text{Transposing }x \text{ from R.H.S to L.H.S}$

$\implies 2x + x= 180$

       $\text{Simplifying...}$

$\implies 3x= 180$

       $\text{Transposing }3\text{ from L.H.S to R.H.S}$

$\implies x= \dfrac{180}{3}$

       $\text{Simplifying...}$

$\implies x= 60^{o}$

 $\therefore \text{ }\text{ The angle is }60^{o}$