find the angle which is equal to twice of its
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Let the another angle be x
It's complement is 2x
Complementary angle = Two angles whose sum is 90°
A/Q 2x+x=90
3x=90
x=90/3
x=30
As first angle is 30
So second angle = 30×2=60
To check 60+30=90
And 60 is twice its complements i.e 30
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