find the angle which is one fifth of its complement...????
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Answered by
37
Let the angle be x
it's complement be 90-x
x = 1/5 (90-x)
5x = 90-x
6x = 90
x = 90/6
x = 15
it's complement be 90-x
x = 1/5 (90-x)
5x = 90-x
6x = 90
x = 90/6
x = 15
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Answered by
14
LET THE ANGLE BE X
THE OTHER ANGE IS X/5
X+X/5=90 DEGREE
LCM=5
5X/5+X/5=90 DEGREE
6X/5=90 DEGREE
6X=90*5
6X=450
X=450/6
X=75
THE OTHER ANGLE IS X/5
75/5
=15 DEGREE
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