find the angle which is onefifth of its complement
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let the angle b x
its complemeñt will b 90-x
therefore
x=1/5(90-x)
x=18-x/5
x+x/5=18
6x/5=18
6x=90
x=15
its complemeñt will b 90-x
therefore
x=1/5(90-x)
x=18-x/5
x+x/5=18
6x/5=18
6x=90
x=15
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