find the angle whose complement is 1/3 of its supplement.
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17
Let the angle be x
complement of x is (90 − x)°
supplement of x is (180 − x)°
A/q,
(90 − x)° = (1/3) × (180 − x)°
⇒ 270° − 3x = 180°− x
⇒ 270° − 180° = 3x − x
⇒ 2x = 90°
∴ x = 45°
complement of x is (90 − x)°
supplement of x is (180 − x)°
A/q,
(90 − x)° = (1/3) × (180 − x)°
⇒ 270° − 3x = 180°− x
⇒ 270° − 180° = 3x − x
⇒ 2x = 90°
∴ x = 45°
Answered by
0
The angle is 60°
1/3×180
i.e 60
1/3×180
i.e 60
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