Question

find the angle whose complement is one third of its supplement​

Answer 1

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Let the angle be 'x°'

Then complement of that angle -- (90- x)°

Supplement of that angle -- (180 - x)°

A/Q ---.>

90 - x = 1/3( 180 - x)

90 - x = 60 - x/3

-x + x/3 = 60 - 90

[ - 3x + x] / 3 = - 30

-2x/3 = -30

x = 30 x 3/2

x = 45°

The required angle is 45°

Hope This Helps You!

Answer 2

Answer:

Step-by-step explanation:

Let the angle be 'x°'

Then complement of that angle -- (90- x)°

Supplement of that angle -- (180 - x)°

A/Q ---.>

90 - x = 1/3( 180 - x)

90 - x = 60 - x/3

-x + x/3 = 60 - 90

[ - 3x + x] / 3 = - 30

-2x/3 = -30

x = 30 x 3/2

x = 45°

The required angle is 45°