find the angle whose complement is one third of its supplement
Answers
Answered by
12
hey...
dude...
let the angle be X ... then..
and it's complement be 90-- X
and it's supplement is 180-- X..
now..
a/q..
90--X= 1/3*180--X.
270--3X= 180--X
270--180=3X--X
90= 2X ..
X = 90/2
X..== 45...
hope it helps you...
be.. brainly.....
by...
rößhàñ....
#####
dude...
let the angle be X ... then..
and it's complement be 90-- X
and it's supplement is 180-- X..
now..
a/q..
90--X= 1/3*180--X.
270--3X= 180--X
270--180=3X--X
90= 2X ..
X = 90/2
X..== 45...
hope it helps you...
be.. brainly.....
by...
rößhàñ....
#####
Answered by
13
Let the angle be x
It's complement be = 90-x
It's supplement be = 180-x
Now
A/Q
90-x=1/3×(180-x)
270-3x=180-x
270-180=3x-x
90=2x
X=90/2
X=45
It's complement be = 90-x
It's supplement be = 180-x
Now
A/Q
90-x=1/3×(180-x)
270-3x=180-x
270-180=3x-x
90=2x
X=90/2
X=45
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