Find the angle whose compliment is one third of its supplement
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Answered by
2
Answer:
let the angle be x
By solving (90-x) = 1/3(180-x)
we will get the solution as 45°
Answered by
3
Let the the required angle = x
Sum of complementary angles = 90
So, complement of of an angle x = (90 − x)°
Sum of supplementary angles =180
So. supplement of an angle x = (180 − x)°
By the problem:
1/3(180-x)=(90-x)
180-x=3(90-x)
180-x=270-3x
3x-x=270-180
2x=90
x={90}/{2}=45
Hopefully it’s helpful for you
Thanks
Sum of complementary angles = 90
So, complement of of an angle x = (90 − x)°
Sum of supplementary angles =180
So. supplement of an angle x = (180 − x)°
By the problem:
1/3(180-x)=(90-x)
180-x=3(90-x)
180-x=270-3x
3x-x=270-180
2x=90
x={90}/{2}=45
Hopefully it’s helpful for you
Thanks
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