find the angle whose supplement is 6 times its complement
Answers
Answered by
13
Let the angle be x.
Supplement = 180 - x
Complement = 90 - x
180 - x = 6(90-x)
180 - x = 540 - 6x
-x + 6x = 540 - 180
5x = 360
x = 360÷5
=72
Supplement = 180 - x
Complement = 90 - x
180 - x = 6(90-x)
180 - x = 540 - 6x
-x + 6x = 540 - 180
5x = 360
x = 360÷5
=72
anshikachikkara76:
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Answered by
5
Here is the answer
Let the angle be x
It's supplement = 180 - x
It's complement = 90 - x
Now,
180 - x = 6(90 - x)
Solve this
Sorry it's 72
Let the angle be x
It's supplement = 180 - x
It's complement = 90 - x
Now,
180 - x = 6(90 - x)
Solve this
Sorry it's 72
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