find the angle whose supplement is 6 times its complement
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6(90-x) = 180 - x
540 - 6x = 180 - x
540 - 180 = 6x - x
5x = 360
x = 360/5
x = 72°
The angle is 72°
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540 - 6x = 180 - x
540 - 180 = 6x - x
5x = 360
x = 360/5
x = 72°
The angle is 72°
Hope it helps.
Mark me as brainlist.
Anonymous:
one more time
Answered by
0
If sum of two angles equals to 90 degree they are said to be complement
If sum of two angles equals to 180 degree then they are said to be supplement .
So,
Let angle be x
So supplement =180-x
Complement of angle =90-x
So,
180-x=6(90-x)
180-x=540-6x
6x-x=540+180
5x=720
x=144
Angle equals to 144
Hope this helps you !!!
Do mark me the brainliest!!!
If sum of two angles equals to 180 degree then they are said to be supplement .
So,
Let angle be x
So supplement =180-x
Complement of angle =90-x
So,
180-x=6(90-x)
180-x=540-6x
6x-x=540+180
5x=720
x=144
Angle equals to 144
Hope this helps you !!!
Do mark me the brainliest!!!
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