find the angle x and y respectively in the given figure
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In △TCE, we have
x=∠TCE+∠TEC (Exterior angle property)
x= 35°+31°
x= 66°
In △SBD , we have
∠AST=∠SBD+∠SDB
∠AST=30° +36° =66°
In △ATS, we have
y+x+∠AST=180°
(Angle sum property)
y+66°+66°=180°
y=180°- (66°+66°
⇒y=48
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