Question

Find the angle x in Trapezium ABCD​

Answer 1

Answer:

x=105° ㄥBPD=120°

Step-by-step explanation:

In Trapezium ABCD, AB||DC.

Therefore, ㄥBAD = ㄥCDA

Since, ㄥCDA = 90°( Given ), therefore ㄥBAD = 90°

Following the angle sum property of a quadrilateral, ㄥBAD(45°) + ㄥCDA(90°) + ㄥBAD(90°) + ㄥABC(30°+x) = 360°

Therefore, 30+x = 135

=> x = 105°

Following same procedure of quadrilateral PBCD, we get ㄥBPD = 120°

Thank You.

Peace :-)