Find the angleDAE and angleADB ..Step by step explanation please
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C + A= 180(sum of opp. Angles of a cyclic quad. Is 180)
So, A = 180 - 110
A= 70
In Triangle ADB
ADB + DBA + DAB = 180(Angle sum property of triangle)
So, ADB = 50
In Triangle ADB
DAE = ADB + ABD(Exterior angle is equal to sum of its opp. 2 interior angles)
DAE= 50 + 60= 110
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