find the angles in which the angle whose complement is one sixth of its supplement
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Let the angle be A.
complement of an angle A is 90 deg. - A
supplement of that angle is 180 deg - A
given the complement is 1/6 th of supplement.
=> 90 - A = 1/6 *(180 - A)
= 30 - A/ 6
5A/6 = 60 deg.
solving that A = 72 deg.
complement of an angle A is 90 deg. - A
supplement of that angle is 180 deg - A
given the complement is 1/6 th of supplement.
=> 90 - A = 1/6 *(180 - A)
= 30 - A/ 6
5A/6 = 60 deg.
solving that A = 72 deg.
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