Question

Find the angles of a parallelogram ABCD in which angelA = 2angleB.​

Answer 1

Answer:

good question good question

Answer 2

Answer:

∠A = 120°, ∠B = 60°, ∠C = 120°, ∠D = 60°

Step-by-step explanation:

In the parallelogram ABCD, ∠A = 2∠B

For any parallelogram ABCD, ∠A  = ∠C and ∠B = ∠D

Since parallelogram ABCD is a quadrilateral, ∴ ∠A + ∠B + ∠C + ∠D = 360°

=> 2∠B + ∠B + ∠∴A + ∠B = 360°

=> 2∠B + ∠B + 2∠B + ∠B = 360°

=> 6∠B = 360°

∴ ∠B = 60° = ∠D

∴ ∠A = ∠C = 120°

∴ ∠A = 120°, ∠B = 60°, ∠C = 120°, ∠D = 60°