find the angles of a parallelogram ABCD in which angle A = 2 angleB
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108
We know that opposite angles of a parallelogram are equal.
The sum of all angles of a parallelogram is equal to 360*.
a=2b
So,
a+a+b+b=360
2b+2b+b+b=360
6b=360
b=60
a=60*2=120
Therefore the angles of the parallelogram are 120*, 60*, 120*, and 60*.
The sum of all angles of a parallelogram is equal to 360*.
a=2b
So,
a+a+b+b=360
2b+2b+b+b=360
6b=360
b=60
a=60*2=120
Therefore the angles of the parallelogram are 120*, 60*, 120*, and 60*.
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78
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