find the angles of a parallelogram ABCD in which angle A=2 angleB
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Let angle B be x
Then, A is 2x
Sum of interior angles of a parallelogram is 360°
If A is 2x then C is also 2x (because opposite angles are equal)
If B is x then D is also x (because opposite angles are equal)
ATQ,
2x+x+2x+x=360
6x=360
x=60°
B and D are 60°
A and C are 60*2=120°
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