Find the angles of a parallelogram ABCD in which ZA = 2 ZB.
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Answer:
120°, 60°, 120° and 60°
Step-by-step explanation:
Angle A = 2 Angle B
Angle A and Angle B are adjacent angles.
=> Angle A + Angle B = 180°
=> 2B + B = 180°
=> 3B = 180°
=> B = 180 ÷ 3
=> Angle B = 60°
Angle A = 120°
Angle C = 120°
Angle D = 60°
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