Question

Find the angles of a parallelogram in which one angle is 2/5 of its adjacent angle

Answer 1

✬ Amgles are = 128.57 & 51.42 ✬

Step-by-step explanation:

Given:

• One angle of parallelogram is 2/5 times of adjacent angle.

To Find:

• What are the measures of angles?

Solution: Let the adjacent angle of ||gm be x. Therefore,

➱ One angle = 2/5 times of x = 2x/5

As we know that

★ Sum of Adjacent ∠s = 180° ★

A/q

• One angle = 2x/5° & another angle = x°

$\implies{\rm }$ 2x/5 + x = 180

$\implies{\rm }$ 2x + 5x/5 = 180

$\implies{\rm }$ 7x = 180 $\times$ 5

$\implies{\rm }$ 7x = 900

$\implies{\rm }$ x = 900/7

$\implies{\rm }$ x = 128.57

So,

➢ Adjacent angle is x = 128.57° and

➢ Another angle is 2x/5

=> 2/5 $\times$ 128.57

=> 51.42°

Answer 2

$\huge{\mathbb{\red{ANSWER}}}$

⭐Angles are = 128.57 & 51.42 ⭐

$\huge{\mathbb{\red{Given}}}$

One angle of parallelogram is 2/5 times of adjacent angle.

$\huge{\mathbb{\red{To find}}}$

What are the measures of angles?

$\huge{\mathbb{\red{solutions}}}$

Let the adjacent angle of ||gm be x. Therefore,

➱ One angle = 2/5 times of x = 2x/5

As we know that

★ Sum of Adjacent ∠s = 180° ★

A/q

One angle = 2x/5° & another angle = x°

\implies{\rm }⟹ 2x/5 + x = 180

\implies{\rm }⟹ 2x + 5x/5 = 180

\implies{\rm }⟹ 7x = 180 \times× 5

\implies{\rm }⟹ 7x = 900

\implies{\rm }⟹ x = 900/7

\implies{\rm }⟹ x = 128.57

So,

➢ Adjacent angle is x = 128.57° and

➢ Another angle is 2x/5

=> 2/5 \times× 128.57

=> 51.42°

$\huge{\mathbb{\red{Angle( 51.42)}}}$