find the angles of a triangle 3:7:8
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Sum of angles of triangle=180°
Let the angles be 3x, 7x, 8x
3x+7x+8x=180°
18x=180°
x=180°/18
x=10
So, angles are
3(10)=30°
7(10)=70°
8(10)=80°
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Answer:
∠A = 30°;
∠B = 70°;
∠C = 80°;
Step-by-step explanation:
Ratio of the angles of a triange is 3:7:8
let the proportional value be x
then the angles are
∠A = 3x ; ∠B=7x ; ∠C =8x
=> 3x+7x+8x = 180° (sum of all 3 angles of a Δ'le )
=> 18x = 180°
=> x = 180°/18 = 10°
=> the angles are
∠A = 3(10°) = 30°;
∠B=7(10°) = 70°;
∠C =8(10°) = 80°;
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