Math, asked by prateekshamk01, 6 months ago

find the angles of a triangle 3:7:8

Answers

Answered by Anonymous
2

Sum of angles of triangle=180°

Let the angles be 3x, 7x, 8x

3x+7x+8x=180°

18x=180°

x=180°/18

x=10

So, angles are

3(10)=30°

7(10)=70°

8(10)=80°

Answered by ravi2303kumar
0

Answer:

∠A  =  30°;

∠B  =  70°;

∠C  =  80°;

Step-by-step explanation:

Ratio of the angles of a triange is 3:7:8

let the proportional value be x

then the angles are

∠A = 3x ; ∠B=7x ; ∠C =8x

=> 3x+7x+8x = 180° (sum of all 3 angles of a Δ'le )

=> 18x = 180°

=> x = 180°/18 = 10°

=> the angles are

∠A = 3(10°) =  30°;

∠B=7(10°) =  70°;

∠C =8(10°) =  80°;

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