find the angles of a triangle if it is an isosceles triangle with vertex angle 50 degree
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let triangle be ABC
(I am using short forms like angle means a)
aA =50° given
acc to angle sum property
aA +aB+aC=180°
and angles opposite to equal sides of an isosceles triangle are equal
so let both a be x
x+x+50=180
2x=180-50
2x=130
x=130/2
x=65
so angles are 65° each
(I am using short forms like angle means a)
aA =50° given
acc to angle sum property
aA +aB+aC=180°
and angles opposite to equal sides of an isosceles triangle are equal
so let both a be x
x+x+50=180
2x=180-50
2x=130
x=130/2
x=65
so angles are 65° each
aayushkalia16:
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