Find the angles of an isosceles triangle if each of two equal angles is half of the third angle.
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Let the third angle be x
And equal angle will be of x/2
Then, converting in equation
x/2+x/2+x=180
(x+x+2x)/2=180
4x=360
x=360/4
x=90
Then the equal angles will be of 90/2=45°.
Angles are 90°, 45,45
I hope this much will help you
And equal angle will be of x/2
Then, converting in equation
x/2+x/2+x=180
(x+x+2x)/2=180
4x=360
x=360/4
x=90
Then the equal angles will be of 90/2=45°.
Angles are 90°, 45,45
I hope this much will help you
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