Question

find the angles of parallelogram abcd in which angleA=2angleB.​

Answer 1

Answer:

AngleA=60°

AngleB=120°

AngleC=60°

AngleD=120°

Step-by-step explanation:

Given:- A parallelogram in which

AngleA=AngleB

To find:- Angle(A,B,C,D)

Solution:- In parallelogram ABCD

AngleA + AngleB = 180°

{co-interior angles are supplementary}

or, 2angleB + AngleB= 180°(angleA = 2angelB)

or, 3angleB=180°

or,. angleB=180/3=60°

=> AngleA= 2×60=120°

Now,

angleA=angleC=120° ( opp. angles of parallelogram)

and,

angleB=angleD=60° (opp.angles of parallelogram)

hope you like it....