Question

find the angles of parallelogram ABCD in which <A=2<B​

Answer 1

Answer:

Step-by-step explanation:

Given : angle A = 2 angle B

We know in parallelogram the adjacent angles have sum 180°.

A and B are adjacent angles

So,

angle A + angle B = 180°

2B + B = 180°

3B = 180

B = 60°

A = 2 × 60° = 120°

B = D = 60° ( opposite angle of parallelogram)

A = C = 120° ( opposite angle of parallelogram)