Find the angles of the parallelogram ABCD if angle C= 2/3 angle D.
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Given:
angle C= 2/3 angle D
To find:
All the angles of the parallelogram.
Solution:
1) In the parallelogram, the opposite angles are equal to each other.
so in parallelogram
- ∠A = ∠C = x
- ∠B = ∠D = y
2) By the angle sum property of the parallelogram,
- x+x+y+y = 360°
According to the question
x = 2y/3
- 2y/3+2y/3+y+y = 360°
- (2y+2y+3y+3y)/3 = 360°
- 10y/3 = 360°
- y = 108°
x = 2y/3
- x = 2×108/3
- x = 72°
The angles of the parallelogram are 72°, 108°, 72°, and 108°.
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