find the angles of the square using a circle
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All sides of a square being equal, the angles subtend by each side at the centre are equal...
∠AOB=∠BOC=∠COD=∠DOA= x(say)
SInce, the sum of the angles round a point =360
therefore,
∠AOB+∠BOC+∠COD+∠DOA=360
x+x+x+x=360
4x=360
x=90
Hope this helps mate!
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