find the angles of the triangle which are in the ratio 3:4:5
Answers
Answered by
3
let the common ratio = x
3x:4x:5x
sum of angles of a triangle = 180
3x+4x+5x = 180
12x = 180
x = 180/12
x = 15
3(15) = 45 degree
4(15) = 60 degree
5(15) = 75 degree
HOPE IT HELPS YOU...
3x:4x:5x
sum of angles of a triangle = 180
3x+4x+5x = 180
12x = 180
x = 180/12
x = 15
3(15) = 45 degree
4(15) = 60 degree
5(15) = 75 degree
HOPE IT HELPS YOU...
Answered by
3
Here is your answer dear ⬇️⬇️
▶️ Let the first angle be 3x
▶️Let the second angle be 4x
▶️Let the third angle be 5x
⚜️ Measure of angles in a triangle = 180°
ATQ,
3x + 4x + 5x = 180
12x = 180
x =![\frac{180}{12} \frac{180}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B180%7D%7B12%7D)
x = 15
✔️ First angle is 3x
i.e. 3 × x
= 3 × 15
= 45°
✔️ Second angle is 4x
i.e. 4 × x
= 4 × 15
60°
✔️ Third angle is 5x
i.e. 5 × x
= 5 × 15
= 75°
▶️ Let the first angle be 3x
▶️Let the second angle be 4x
▶️Let the third angle be 5x
⚜️ Measure of angles in a triangle = 180°
ATQ,
3x + 4x + 5x = 180
12x = 180
x =
x = 15
✔️ First angle is 3x
i.e. 3 × x
= 3 × 15
= 45°
✔️ Second angle is 4x
i.e. 4 × x
= 4 × 15
60°
✔️ Third angle is 5x
i.e. 5 × x
= 5 × 15
= 75°
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