Question

find the angles of the triangles if each of the angles were x-10 x-20 X/2 - 10
find x
irrelevant answers will be reported ​

Answer 1

Answer:

we know,

The sum of all angles of any triangle is equal to 180°.

Here given,

first angle = ( x -40)°

second angle = (x -20)°

third angle = (x/2 - 10)°

first angle + second angle + third angle = 180°  

( x -40)° + (x -20°) + (x/2 - 10)° = 180°  

(x + x + x/2) -(40 + 20 + 10) = 180°  

5x/2 = 250°  

x = 100°

First Angle= (100°-40°)= 60°

Second Angle= (100°-20°)= 80°

Third Angle= ((100/2)°-10)= 50°-10°=40°

Please mark me brainliest