Question

find the angles of triangle if they are in the ratio 5:4:3 for class 9
who will give correct answer I will mark as brainlist

Answer 1

Here's ur answer ,

The perimeter of given triangle =96 cm

The sides of triangle are in ratio 5:4:3 ,

Let x be the common multiple of the sides ,

5x, 4x,3x 

The perimeter of triangle = sum of all sides of triangle 
96=5x+4x+3x
96=12x
96÷12=x
x=8

The side of triangle are ,

5x=5×8=40
4x=4×8=32
3x=3×8=24


Let ,
a =40
b=32
c=24


The area of triangle by herons formula ,

s 
= a+b+c÷2
=40+32+24÷2
=96÷2
=48

A=
\sqrt{s(s - a)(s - b)(s - c)}s(s−a)(s−b)(s−c)​ 
=
\sqrt{48(48 - 40)(48 - 32)(48 - 24)}48(48−40)(48−32)(48−24)​ 

=
\sqrt{48 \times 8 \times 16 \times 24}48×8×16×24​ 
=
\sqrt{147456}147456​ 

=384 square cm 


The area of triangle =384 square cm


Hope it helps you ! 

Answer 2

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Here is your answer
Let the angle of the triangle are
5x , 4x ,and 3 x

As Sum of all angles of the triangle is 180°
so
$5x + 4x + 3x = 180 \\ 12x = 180 \\ x = \frac{180}{12} \\ x = 15$
Hence The angles are
5× 15 = 75°
4×15. = 60°
3× 15 = 45°


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