Question

Find the angles the vectors (1,-1,1) and (2,3,6)​

Answer 1

Step-by-step explanation:

write coordinates as vector form (1,-1,1) and (2,3,6)

$let \: a \: vector \: = i - j +k \\ \\ and \: \: b \: \: vector \: = 2i + 3j + 6k \\ \\ now \: \: \: vector \: (a.b) = |a| |b| \cos(x) \\ \\ ( i - j +k )(2i + 3j + 6k ) = ( \sqrt{1 + 1 + 1} ) \times \sqrt{(4 + 9 + 6)} \cos(x) \\ \\ (2 - 3 + 6) = ( \sqrt{3}) ( \sqrt{19} ) \cos(x) \\ \\ 5 = \sqrt{57} \cos(x) \\ \\ \cos(x) = \frac{5}{ \sqrt{57} } \\ \\ x = { \cos(x) }^{ - 1} ( \frac{5}{ \sqrt{ 57} } )$

Required ans

Answer 2

please mark it as brainlist answer.