Find the angles which are adjacent and form an angle of 140 degrees. The smaller angle is 28 degrees less than larger angle.
Answers
Answered by
162
Let the larger angle is x°.
∴, the smaller angle is (x°-28°).
By the given condition,
x°+x°-28°=140°
or, 2x°=140°+28°
or, x°=168°/2
or, x°=84°
∴, the smaller angle is: 84°-28°=56°
∴, the smaller angle is (x°-28°).
By the given condition,
x°+x°-28°=140°
or, 2x°=140°+28°
or, x°=168°/2
or, x°=84°
∴, the smaller angle is: 84°-28°=56°
Answered by
70
The two adjacent angles add up to 140.
Lets say the larger angle is x.
and the smaller is x-28.
Therefore the sum of the two should give 140.
x + x-28= 140
2x-28= 140
2x=140+28=168
2x=168(divide both sides by two)
x=84 (the larger angle)
84-28= 56 (the smaller angle)
The two angles are 84 and 56.
Lets say the larger angle is x.
and the smaller is x-28.
Therefore the sum of the two should give 140.
x + x-28= 140
2x-28= 140
2x=140+28=168
2x=168(divide both sides by two)
x=84 (the larger angle)
84-28= 56 (the smaller angle)
The two angles are 84 and 56.
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