Find the angles x, y in the following circles with centre O.
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Here,
∠OPN= 25°
PN is a tangent at point N
so ∠ONP = 90°
In ∆ONP,
∠NOP = 180- (90+25)= 180-115= 65°
So,
X = 180-65=115°( supplementary angles)
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