Question

Find the anglesof a parallelogram ABCD in which Angle A= 2 Angle B​

Answer 1

Step-by-step explanation:

angleA=angleC , angleB = angleD{ opp. angle of parallelogram are equal}

angle A+ angle B+ angle C+ angle D=360°{ sum of all angle of quadrilateral}

2<B+<B+<A+<B=360

4<B+2<B=360°

6<B=360°

<B= 60°

<A=<C= 2<B= 2*60°=120

<B=<D= 60°