Question

Find the angular acceleration of a particle in circular motion, which slows down from 300 rpm to 600 rpm in 20 s​

Answer 1

Explanation:

One of the equation's for circular motion states that:

V= V' + at

where, V is the final angular velocity

V' is the initial angular velocity

a is the angular acceleration

t is time taken to attain V from V'

Now, V = 600 rpm =10 rps or 1 rotation in 0.1 sec.

hence, 2(pi) radians are traversed in 0.1 sec. ,then in 1 sec. angle traversed in 20(pi) radians. Hence, V = 20(pi) radians/sec.

=> a= V/t. (V' =0)

=>. a= 2(pi) rad./sec.^2 or 6.28 rad./sec.^2

Answer 2

Answer:

One of the equation's for circular motion states that:

V= V' + at

where, V is the final angular velocity

V' is the initial angular velocity

a is the angular acceleration

t is time taken to attain V from V'

Now, V = 600 rpm =10 rps or 1 rotation in 0.1 sec.

hence, 2(pi) radians are traversed in 0.1 sec. ,then in 1 sec. angle traversed in 20(pi) radians. Hence, V = 20(pi) radians/sec.

=> a= V/t. (V' =0)

=>. a= 2(pi) rad./sec.^2 or 6.28 rad./sec.^2