find the angular elevation of the sun when the shadow of a 10 m long pipe is 10√3 metres.
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Let AB be the pool and let AC be it's shadow.
Let the angle of elevation of the sun be ¢ .
Then,
/_ ACB = ¢° , /_ CAB = 90°.
AB = 10 m and AC = 10√3 m.
From right ∆ CAB , we have
tan ¢ = AB/AC = 10/10√3 = 1/√3
=> ¢ = 30°
Hence,
The angular elevation of the sun is 30°.
Let the angle of elevation of the sun be ¢ .
Then,
/_ ACB = ¢° , /_ CAB = 90°.
AB = 10 m and AC = 10√3 m.
From right ∆ CAB , we have
tan ¢ = AB/AC = 10/10√3 = 1/√3
=> ¢ = 30°
Hence,
The angular elevation of the sun is 30°.
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length of pole = 10 m (perpendicular)
Shadow = 10√3 m (base)
Tanθ = P/B
10/10√3
1/√3
Tan(30°)= 1/√3
Therefore, elevation of the sun is 30°
Shadow = 10√3 m (base)
Tanθ = P/B
10/10√3
1/√3
Tan(30°)= 1/√3
Therefore, elevation of the sun is 30°
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