Question

find the angular momentum of an electron when it is in second bohr orbit of hydrogen atom​

Answer 1

Angular momentum = mvr or nh/2π (according to bohr)

•°•, L = 2 × 6.634 ×10^-34 ÷ 2π

= 2.11 × 10^-34 kg/sm²

PLEASE MARK IT AS BrAinLIesT.

Answer 2

Answer:

Angular momentum of an electron in the fourth orbit in Bohr's hydrogen atom is $2.10*10^{-34}$

Explanation:

• The angular momentum $(L)$  gives the quantity of rotation in a rotating body

• From Bohr's postulate for allowed orbits, angular momentum is given by the formula

         $L=n\frac{h}{2\pi }$

         where,

         $n$- the principal quantum number

         $h=6.62*10^{-34}$(Planck's constant)

for the second Bohr's orbit

the principal quantum number $n=2$

⇒

the angular momentum is $L=2*\frac{h}{2\pi } =\frac{h}{\pi }$

$L=6.626*10^{-34}/3.14=2.10*10^{-34}$